Case III:- River boat problems Now initially a boat or swimmer is at one bank of river (let say at point A) swimmer or boat man wants to cross the river and to reach the other bank of river by the concept of relative motion.

Vbr = = Vb – Vr

Vb = Vbr + Vr

Along y-axis (perpendicular to river flow)

(Vb)y = (Vbr)y + (Vr)y

(Vb)y = Vbr + 0

Displacement along y-axis = d

Time taken to cross the river = t  Time take to cross the river For minimum time or shortest time to cross the river  But in this case swimmer will not reach just opposite point he will cross the river and reach the other bank of river. Drifting:- Horizontal distance due to river flow, when swimmer reach opposite bank of river. It is denoted by x

Now again    Vbr = Vb - Vr

Along x –axis  (Vbr)x = (Vb)x –(Vr)x

-Vbr sinq = (Vb)x –Vr Disp. Along x-axis (Drifting) = x    Drifting in case of shorter time    Drifting = 0 Vr – Vbr sinq = 0 Unique angle to reach just opposite point of the river Now    General value of time   Down the stream and up the stream

Down the stream   up the stream  Note: Above Case is also applicable in escalator or moving belt.

Example: A river is flowing due east with speed 3 km/hr. A boat is crossing the river with speed 5 km/hr with respect to still water. Fnd time taken by the boat if boat reaches just opposite point on the other bank of river. Given river width is 0.5 Km.

Solution.     Vr = 3km/h

Vbr = 5 km/h

d = 0.5 km

Reaching just opposite point Case:- 4  Rain and umbrella problems Case:- 4  Rain and umbrella problems

A person is moving with light walking speed of 3 km/h observe that rain is falling at angle of 37o with vertical if man increases his speed to 5 km/h he observe that rain is falling now in vertical direction. Find speed of rain with respect to ground.

Solution:-

Let velocity of rain is Case I       3b = 4a-12

Case II:-   a = 5

Now        3b = 4a -12

3b = 4 x 5 - 12    Case I

A motorboat going downstream overcame a raft at a point A;  t = 60 min later it turned back and after some time passed the raft at a distance l = 6.0 km below the point A. Find the velocity  of the flow assuming  that the  engine worked  in one regime in both directions .

Case 2

Two swimmers start swimming from point ‘A’ on one bank  of the river  to reach point ‘B’ lying right across on the other bank. One of them crosses the river along the straight line AB while the other swims at right angles to the stream and then walks the distances that the he has been carried away by the stream with velocity u to reach point ‘B’. Find at what value of u, both will reach point ‘B’ simultaneously? If the stream velocity is v0 = 2.0 km /h and velocity of each swimmer relative to the water is v’ = 2.5 km /h?

Case 3

An elevator car, whose floor – to –ceiling distance is 2.7m, starts ascending with constant  acceleration a = 1.2 m/ s2; 2 s after the start a bolt  starts falling from the ceiling of the car. Find the:

(a) bolt’s free fall time.

(b) Displacement and the distance covered by the bolt during the free fall in references frame fixed to the elevator shaft.

Join any of the batches using this book

## Batch List #### JEE 2023 Physics Online Class

Course : JEE

Start Date : 04.06.2023

End Date : 30.06.2023

Types of Batch : Live Online Class

 Subject M T W T F S S Physics(50 hours) 3:30 PM - - 3:30 PM - 3:30 PM - 