ANGULAR MOMENTUM (ii)  Angular Momentum of a Rigid Body Rotation about a Fixed Axis Uniform Pure Rolling vp = vQ

v - Rw = 0

v = Rw If vp > vQ or v > Rw, the motion is said to be forward slipping and if vp < vQ or v < Rw, the motion is said the backward slipping

Accelerated  Pure Rolling v = Rw at = Ra     Rolling on Rough Incline plane     Isolid  <  Ihollow  or  asolid  > ahollow

tsolid   <   thollow Case

A block of mass m and a cylinder of mass 2m are released on a rough inclined plane, inclined at an angle with the horizontal. The coefficient of friction for all the contact surface is 0.5 find the accelerations of the block and the cylinder.

Assume pure rolling. If the block and cylinder move independently on the incline, their acceleration are      So, both the bodies will move in contact

with each other with common acceleration a which we have to calculate.

Free body diagram of block is as shown.   …..(i)  ….(ii)

From Eqs. (i) and (ii), we get The free body diagram of cylinder is as shown.  And  From Eqs. (iv) and (v), we get Using this in Eq. (iii), we get Case:- Ladder → mass = m, Length = L For equilibrium

fN = 0

N1mg = 0 Substitute value of N1 and f  Case:- Topping and Sliding For translational equilibrium  For rotational equilibrium    block has a tendency to slide before topple block has a tendency to topple before slide block slides down block topples

Join any of the batches using this book

## Batch List #### JEE 2023 Physics Online Class

Course : JEE

Start Date : 04.06.2023

End Date : 30.06.2023

Types of Batch : Live Online Class

 Subject M T W T F S S Physics(50 hours) 3:30 PM - - 3:30 PM - 3:30 PM - 