1. Median of a triangle
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- CBSE Class 7
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Triangle
A triangle is a closed figure made by three line segments. It has three vertices, three sides and three angles.
A triangle ABC is given having three vertices A, B, C and three sides AB, BC, CA and three angles are ∠ABC, ∠ BCA, ∠CAB.
Classification of triangles:
1. With respect to angles are:
(a) Acute-angled triangles
(b) Obtuse-angled triangles
(c) Right-angled traingles
(a) Acute-angled triangles
A triangle in which measurement of each of the three angles are less than 90°.
(b) Obtuse-angled triangle :
A triangle in which one angle is obtuse angle i.e. greater than 90° but less then 180°.
(c) Right-angled triangle:
A triangle in which one angle is exactly 90°.
• The side opposite to the right angle is called the hypotenuse.
• The other two sides are called as the legs of the right-angled triangle (or base and perpendicular).
• In the given figure AC is the hypotenuse and AB and BC are the legs of DABC.
2. Altitude of a triangle
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- CBSE Class 7 Mathematics Book
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- CBSE Class 7
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Medians of a Triangle and Centroid
Medians :-
AB, BC, CA are the sides of and AD is a line segment which intersects side BC of at point D such that AD bisects the side BC. This line segment AD is called the median of .
A median is a line segment which connects a vertex of a triangle to the mid point of the opposite side.
Centroid :-
• Centroid is the point of intersection of all three medians of a triangle.
• In the given figure G is the centroid of
• A centroid of a triangle cuts the median in the ratio 2 : 1
⟹ AG : GD = 2 : 1
3. Exterior angles of a triangle
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- CBSE Class 7 Mathematics Book
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- CBSE Class 7
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- Mathmatics
ALTITUDES OF A TRIANGLE AND ORTHOCENTRE
AD is a line segment which is perpendicular to the side BC of ∆ABC .This line segment AD is called as altitude of ∆
Altitude is also called as height of a triangle. In the given figure AD is the height of ∆ ABC from vertex A to side BC.
• Orthocentre is the meeting point of all three altitudes of a triangle.
• In the given figure H is the orthocentre of ∆ ABC.
• In obtuse-angled triangle the orthocentre lies outside the triangle.
• In Acute-angled triangle the orthocentre lies inside the triangle.
• In a Right-angled triangle, the right angle lies at the vertex at which the right angle is formed.
4. Apply angle sum property of a triangle
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- CBSE Class 7
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Exterior Angle Property of a Triangle -
Illustration 1
Is it possible to draw a triangle whose sides are 3 cm, 4 cm and 7 cm ?
Solution
Sides of a triangle are 3 cm, 4cm, 7 cm.
Here 3 + 4 = 7
and we know that sum of two sides of a triangles is always greater than the third side so it is not possible to draw a triangle whose sides are 3 cm, 4 cm and 7 cm.
Illustration 2
In each of the following there are three positive numbers. State if these numbers could possibly be the lengths of the sides of a triangle.
(i) 2, 3, 4 (ii) 2.5, 1.5, 4
Solution
(i) We have,
2 + 3 > 4, 2 + 4 > 3 and 3 + 4 > 2
That is, the sum of any two of the given numbers is greater than the third number.
So, 2 cm, 3 cm and 4 cm can be the lengths of the sides of a triangle.
(ii) We have,
2.5 + 1.5 ≯ 4.
So, the given numbers cannot be the lengths of the sides of a triangle.
Illustration 3
The length of two sides of a triangle are 12 cm and 15 cm. Between what two measure should the length of the third side fall ?
Solution
Let x cm be the length of the third side.
Then 12 + x > 15; 15 + x > 12 and 12 + 15 > x.
⇒ x > 15 – 12; x > 12 –15 and 27 > x.
⇒ x > 3 ; x > – 3 and 27 > x.
A number greater than 3 is obviously greater than – 3.
∴ x > 3 and 27 > x.
Hence, x lies between 3 cm and 27 cm.
Property : Angles opposite to equal sides of a triangle are equal.
Property : Sides opposite to equal angles of a triangle are equal.
Property : In a right triangle, if a, b are the lengths of the sides and c that of the hypotenuse, then c2 = a2 + b2.
(Hypotenuse)2 = (Base)2 + (Perpendicular)2
Property : If the sides of a triangle are of lengths a, b and c such that c2 = a2 + b2, then the triangle is right angled and the side of length c is the hypotenuse.
Note : Three positive numbers a, b, c in this order are said to form a pythagorean triplet, if
c2 = a2 + b2. Triplets (3, 4, 5) (5, 12, 13), (8, 15, 17), (7, 24, 25) and (12, 35, 37) are some pythagorean triplets.
Illustration 1
The sides of certain triangles are given below. Determine which of them are right triangles :
(i) a = 6 cm, b = 8 cm and c = 10 cm
(ii) a = 5 cm, b = 8 cm and c = 11 cm.
Solution
(i) Here the larger side is c = 10 cm.
We have : a2 + b2 = 62 + 82 = 36 + 64 = 100 = c2.
So, the triangle with the given sides is a right triangle.
(ii) Here, the larger side is c = 11 cm
Clearly, a2 + b2 = 25 + 64 = 89 ≠ c2.
So, the triangle with the given sides is not a right triangle.
Illustration 2
A ladder 25 m long reaches a window of a building 20 m above the ground. Determine the distance of the foot of the ladder from the building.
Solution
Suppose that AB is the ladder, B is the window and CB is the building. Then, triangle ABC is a right triangle, with right angle at C.
∴ AB2 = AC2 + BC2
⇒ 252 = AC2 + 202
⇒ AC2 = 625 – 400 = 225
Illustration 3
A ladder 17 m long reaches a window which is 8 m above the ground on one side of the street. Keeping its foot at the same point, the ladder is turned to the other side of the street to reach a window at a height of 15 m. Find the width of the street.
Solution
Let AB be the street and C be the foot of the ladder. Let D and E be the windows at the height of 8 m and 15m respectively from the ground.
Then, CD and CE are the two positions of the ladder.
In right triangle, DDAC, we have
AC2 + AD2 = CD2
⇒ AC2 = (CD2 – AD2)
= {(17)2 – (8)2} m2 = 289 – 64 = 225 m2
In right triangle, DCBE, we have
CB2 + BE2 = CE2
⇒ CB2 = (CE2 – BE2) = {(17)2 – (15)2} m2 = 64 m2
Hence, width of the street = AB = (AC + CB) = (15 + 8) m = 23 m.
Illustration 4
A tree has broken at a height of 5 m from the ground and its top touches the ground at a distance of 12m from the base of the tree. Find the original height of tree.
Solution
Let AB be the tree and Let C be the point at which it broke.
Then CB takes the position CD.
Original height of tree i.e., AB
i.e. AC + BC⇒ AC + CD (∵
i.e. ∆ACD, using pythagoras theorm, we
CD2 = AC2 + AD2
CD2 = (5)2 + (12)2 = 25 + 144 = 169
CD2 = 132
CD = 13 m
So. height of tree = AC + BC
= AC + CD
= (5+13) m
= 18 m
Hence, height of the tree = 18 m.
5. Two special triangles:
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- CBSE Class 7 Mathematics Book
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- CBSE Class 7
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Angle Sum Property of a Triangle:
The sum of the measures of three angles of a triangle is 180°.
Proof of Angle Sum Property of a Triangle
Given : A triangle ABC.
To prove : ∠ A +∠B +∠C = 180°
Construction : Draw a line segment PQ through A and parallel to BC.
Proof: Mark the angles as indicated in the figure.
Hence, ∠ A +∠B +∠C = 180°
or sum of the angles of a triangle is 180°
ANGLE BISECTORS OF A TRIANGLE AND IN-CENTRE
Angle Bisectors :-
Angle bisector of a triangle is a line segment which bisect the angle and whose end points lies on the vertex and its opposite side.
• In the given figure, AD is the bisector of
So ∠BAD = ∠DAC
Incentre
• In-centre is the meeting point of all three angle bisectors of a triangle.
• In the given figure, I is the Incentre of ∆
• In-centre always lies inside the triangle.
• The perpendicular distance from incentre to the side of triangle is always same.
⇒ IP = IQ = IR
• A circle can be drawn inside the triangle by assuming I as centre and IP as radius.
PERPENDICULAR BISECTOR AND CIRCUMCENTRE
Perpendicular Bisector
It is a line segment which is perpendicular to the side of a triangle and passing through the mid point of the side.
In the given figure MN is the perpendicular bisector for ∆
5. Special triangles
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- CBSE Class 7
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2. With respect to sides are:
(a) Scalene triangles (b) Isosceles triangles (c) Equilateral triangles
(a) Scalene Triangle: A triangle in which no two sides are equal in length is called a scalene triangle.
• Length of all sides and measurement of all angles is different.
(b) Isosceles Triangle
(i) Two sides have same length
(ii) The angles opposite to the equal sides are equal.
If in DABC, AB = AC then ∠B = ∠C this is an isoceles triangle.
Converse is also true
If in a triangle two angles are equal then sides opposite to equal angles are equal in length.
In , if ∠B = ∠C then AB = AC.
(c) Equilateral Triangle
In an equilateral triangle
(i) All sides are equal in length.
(ii) Measurement of each angle is 60°.
In , if AB = BC = AC then ∠A = ∠B =∠C = 60°
or if then ∠A = ∠B = ∠C= 60° AB = BC = AC
6. Sides of a triangle
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Perimeter of a Triangle
The sum of the lengths of the sides of a triangle is called its Perimeter.
In ∆ AC = b, BC = a, AB = c then perimeter is BC + CA + AB = a + b + c
TRIANGULAR INEQUALITY PROPERTY
The sum of the lengths of any two sides of a triangle is always greater than the third side.
AB + BC > AC
AB + AC > BC
AC + BC > AB
The difference between the length of any two sides of a triangle is smaller than the length of the third side.
AB – BC < CA
BC – CA < AB
CA – AB < BC
Example
XY + YZ > XZ
3 + 4 > 5
similary YZ + XZ > XY
4 + 5 > 3
similary XY + XZ > YZ
3 + 5 > 4
7.Right-angles triangles and Pythagoras property
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3. Pythagoras Property of Right-Angled Triangle
In a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the legs.
Converse of Pythagoras Theorem
In a triangle if the square of one side is equal to the sum of the squares of the remaining two sides then the angle opposite to the first side is a right angle.
It is clear that:-
AC2 > AB2 and AC2 > BC2
⇒ AC > AB and AC > BC.
Hence, we can say that in right triangle the hypotenuse is the largest side.
A ∆ABC is such that AB = 4 cm, AC = 3cm, BC = 5 cm and BC2 = AB2 + AC2 52 = 42 + 32,
then measure of ∠A should be 90°.
Note.: If the pythagoras property holds, the triangle must be right angled.
Pythagorian Triplets
It is a set of three natural numbers a, b, c such that a2 + b2 = c2. Such a set of three number it is called as Pythagorean Triplet. For example- (3, 4, 5), (5, 12, 13), (6, 8, 10) etc.