- Books Name
- CBSE Class 6 Mathematics Book
- Publication
- Param Publication
- Course
- CBSE Class 6
- Subject
- Mathmatics
Perimeter
The perimeter of a closed figure is the length of the boundary of the figure.
The idea of perimeter is widely used in our daily life.
- A farmer who wants to fence his field.
- An engineer who plans to build a compound wall on all sides of a house.
- A person preparing a track to conduct sports.
All these people use the idea of ‘perimeter’.
1. Perimeter of Rectangle: The perimeter of a rectangle is the sum of all its sides. The opposite sides of rectangle are equal. If one side is l unit and the other side is b unit, then
2 . Perimeter of a square: All four sides of a square are equal. If one side of a square measures 'a' unit, we can say that both the length and the breadth are a unit each.
The perimeter of a square is equal to four times the length of its sides.
3. Perimeter of a triangle :
Perimeter = AB + BC + CA = a + b + c
Note: In general, if the sides of a polygon are equal, that is, if it is a regular polygon, its perimeter will be the product of the length of its side with the number of sides.
The perimeter of a regular pentagon = 5a units
The perimeter of a regular hexagon = 6a units
The perimeter of a regular octagon = 8a units
where a is the length of one side.
Ex.1 Pinky runs around a square field of side 75 m, Bob runs around a rectangular field with a length of 160 m and breadth of 105 m. Who covers more distance and by how much?
Sol.: Distance covered by Pinky in one round = Perimeter of the square
= 4 × length of a side
= 4 × 75 m = 300 m
Distance covered by Bob in one round = Perimeter of the rectangle
= 2 × (length + breadth)
= 2 × (160 m + 105 m)
= 2 × 265 m = 530 m
Difference in the distance covered = 530 m – 300 m = 230 m.
Therefore, Bob covers more distance by 230 m.
Ex.2 Find the perimeter of a regular pentagon with each side measuring 3 cm.
Sol.: This regular closed figure has 5 sides, each with a length of 3 cm.
Thus, we get
Perimeter of the regular pentagon = 5 × 3 cm = 15 cm
Ex.3 A piece of string is 48 cm long. What will be the lenght of each side if the string is used to form:
(i) a square (ii) an equilateral triangle (iii) an regular octagon .
Sol. (i) one side of the square = Perimeter ¸ 4 = 48 ¸ 4 = 12 cm
(ii) one side of the equilateral triangle = Perimeter ¸ 3 = 48 ¸ 3 = 16 cm
(iii) one side of regular octagon = Perimeter ¸ 8 = 48 ¸ 8 = 6 cm