- Books Name
- Rakhiedu Mathematics Book

- Publication
- Param Publication

- Course
- CBSE Class 10

- Subject
- Mathmatics

**INTRODUCTION **

In previous classes, we have studided certain constructions using a ruler and a compass. There are : bisecting an angle, drawing the perpendicular bisector of a line segment, construction of some triangle, etc. We have also given their justifications. Here, we shall study some more constructions taking into use the above pervious knowledge. Also, we shall give mathematical reasoning underlying these constructions.

**Divison of A line segment : **

In order to divide a line segment internally in a given ratio m : n, where both m and n are positive integers, we follow the following steps :

**Steps of construction : **

**(i)** Draw a line segment AB of given length by using a ruler.

**(ii) ** Draw any ray AX making a suitable acute angle with AB.

**(iii) ** Along AX draw (m + n) arcs intersecting the rays AX at A_{1}, A_{2} ............, A_{m}, A_{m+1}, ........., A_{m + n} such that AA_{1} = A_{1A2} =...............= A_{m+n–1} A_{m+n}

**(iv) ** Join B Am+n

**(v)** Through the point A_{m} draw a line parallel to A_{m+n} B by making *∠*AA_{m} P = *∠*AA_{m+n} B.

Suppose this line meets AB at point P.

The point P so obtained is the required point which divides AB internally in the ratio m : n.

**Illustration **

Divide a line segment of length 12 cm internally in the ratio 3 : 2.

**Solution**

Steps of construction :

(i) Draw a line segment AB = 12 cm by using a ruler.

(ii) Draw a ray making a suitable acute angle *∠*BAX with AB.

(iii) Along AX, draw 5 ( = 3 + 2) arcs intersecting the rays AX at A_{1}, A_{2}, A_{3}, A_{4} and A_{5} such that

AA_{1} = A_{1}A_{2} = A_{2}A_{3} = A_{3}A_{4 }= A_{4}A_{5}